10 条题解

  • 2
    @ 2025-4-1 19:48:36

    6

    • 1
      @ 2025-3-15 14:44:34

      #include<bits/stdc++.h> using namespace std; int main(){ int a,b; cin>>a>>b; cout<<a+b; return 0; }

      • 1
        @ 2025-3-4 22:49:10
        using namespace std;
        int sum(int a,int b)
        {
            int ss = a+b;
            return ss;
        }
        int main()
        {
            int a,b,s;
            cin>>a>>b;
            s = sum(a,b);
            cout<<s;
            return 0;
        }
        • 1
          @ 2025-1-25 18:06:03

          kl.jfnl;fnklfgldmcv cxcmc k.dfvnfld

          • 1
            @ 2024-10-6 21:38:55

            #include using namespace std;

            int main () { cin >> *new int () >> *new int (); cout << *(new int () - 16) + *(new int () - 16) + 1; return 0; }

            • 1
              @ 2024-10-1 14:02:11
              #include<bits/stdc++.h>
              using namespace std;
              
              int main(){
                  int a,b;
                  cout<<a+b;
                  return 0;
              }
              

              废话不多说,定义两个变量直接输出它们的和即可,别整那些没用的。

              • 1
                @ 2024-2-22 9:56:40
                //位运算
                #include <bits/stdc++.h>
                using namespace std;
                int add(int a, int b) {
                    if (b == 0) return a;
                    return add(a ^ b, (a & b) << 1);
                }
                int main() {
                    int a, b; scanf("%d%d", &a, &b);
                    printf("%d\n", add(a, b));
                    return 0;
                }
                
                //暴力
                #include <bits/stdc++.h>
                using namespace std;
                int main() {
                    int a, b; scanf("%d%d", &a, &b);
                    for (int i = min(2 * a, 2 * b);i <= max(2 * a, 2 * b); i++)
                        if (a + b == i) {
                            printf("%d", i); 
                            return 0;
                        }
                }
                
                //能过的
                #include <bits/stdc++.h>
                #define ___ int
                #define $$$ main
                #define _$_$_ return
                #define _ cin
                #define $ cout
                #define __ using
                #define $$ namespace
                #define o_o std
                __ $$ o_o;
                ___ $$$(){
                    ___ _$o$_,$o_o$;
                    _ >> _$o$_ >> $o_o$;
                    $ << _$o$_ + $o_o$;
                    _$_$_ 0;
                }
                
                //不用变量
                #include <iostream>
                using namespace std;
                
                int main ()
                {
                    cin >> *new int () >> *new int ();
                    cout << *(new int () - 16) + *(new int () - 16);
                    return 0;
                }
                
                • @ 2024-2-22 10:55:40

                  改一下不用变量的做法

                  //不用变量
                  #include <iostream>
                  using namespace std;
                  
                  int main ()
                  {
                      cin >> *new int () >> *new int ();
                      cout << *(new int () - 16) + *(new int () - 16) + 1;
                      return 0;
                  }
                  
              • 1
                @ 2023-11-11 18:10:17

                没啥可说的,上代码 #include using namespace std; int main() { int a,b; cin>>a>>b; cout<<a+b; return 0; }

                • 0
                  @ 2025-7-13 21:49:27
                  using namespace std;
                  int main()
                  {
                      char s1[1001],s2[1001];
                      int a[1001] = {},b[1001] = {},c[1001] = {};
                      cin>>s1>>s2;
                      int lena = strlen(s1);
                      int lenb = strlen(s2);
                      for(int i=0;i<=lena-1;i++)
                      {
                          a[i] = s1[lena - 1 - i] - '0';
                      }
                      for(int i=0;i<=lenb-1;i++)
                      {
                          b[i] = s2[lenb - 1 - i] - '0';
                      }
                      int lenc;
                      if(lena>lenb)
                      {
                          lenc = lena;
                      }
                      else
                      {
                          lenc = lenb;
                      }
                      int jw = 0;
                      for(int i=0;i<=lenc-1;i++)
                      {
                          c[i] = a[i]+b[i]+jw;
                          jw = c[i]/10;
                          c[i] = c[i]%10;
                      }
                      if(jw==1)
                      {
                          cout<<1;
                      }
                      for(int i=lenc-1;i>=0;i--)
                      {
                          cout<<c[i];
                      }
                      return 0;
                  }
                  
                  
                • 0
                  @ 2025-3-16 20:13:51

                  using namespace std;

                  int main(){ int a,b; cout<<a+b; return 0; }

                  • 1

                  信息

                  ID
                  1
                  时间
                  1000ms
                  内存
                  64MiB
                  难度
                  4
                  标签
                  递交数
                  301
                  已通过
                  134
                  上传者