10 条题解

  • 2
    @ 2025-4-1 19:48:36

    6

    • 1
      @ 2025-3-16 20:13:51

      using namespace std;

      int main(){ int a,b; cout<<a+b; return 0; }

      • 1
        @ 2025-3-15 14:44:34

        #include<bits/stdc++.h> using namespace std; int main(){ int a,b; cin>>a>>b; cout<<a+b; return 0; }

        • 1
          @ 2025-3-4 22:49:10
          using namespace std;
          int sum(int a,int b)
          {
              int ss = a+b;
              return ss;
          }
          int main()
          {
              int a,b,s;
              cin>>a>>b;
              s = sum(a,b);
              cout<<s;
              return 0;
          }
          • 1
            @ 2025-1-25 18:06:03

            kl.jfnl;fnklfgldmcv cxcmc k.dfvnfld

            • 1
              @ 2024-10-6 21:38:55

              #include using namespace std;

              int main () { cin >> *new int () >> *new int (); cout << *(new int () - 16) + *(new int () - 16) + 1; return 0; }

              • 1
                @ 2024-10-1 14:02:11
                #include<bits/stdc++.h>
                using namespace std;
                
                int main(){
                    int a,b;
                    cout<<a+b;
                    return 0;
                }
                

                废话不多说,定义两个变量直接输出它们的和即可,别整那些没用的。

                • 1
                  @ 2024-2-22 9:56:40
                  //位运算
                  #include <bits/stdc++.h>
                  using namespace std;
                  int add(int a, int b) {
                      if (b == 0) return a;
                      return add(a ^ b, (a & b) << 1);
                  }
                  int main() {
                      int a, b; scanf("%d%d", &a, &b);
                      printf("%d\n", add(a, b));
                      return 0;
                  }
                  
                  //暴力
                  #include <bits/stdc++.h>
                  using namespace std;
                  int main() {
                      int a, b; scanf("%d%d", &a, &b);
                      for (int i = min(2 * a, 2 * b);i <= max(2 * a, 2 * b); i++)
                          if (a + b == i) {
                              printf("%d", i); 
                              return 0;
                          }
                  }
                  
                  //能过的
                  #include <bits/stdc++.h>
                  #define ___ int
                  #define $$$ main
                  #define _$_$_ return
                  #define _ cin
                  #define $ cout
                  #define __ using
                  #define $$ namespace
                  #define o_o std
                  __ $$ o_o;
                  ___ $$$(){
                      ___ _$o$_,$o_o$;
                      _ >> _$o$_ >> $o_o$;
                      $ << _$o$_ + $o_o$;
                      _$_$_ 0;
                  }
                  
                  //不用变量
                  #include <iostream>
                  using namespace std;
                  
                  int main ()
                  {
                      cin >> *new int () >> *new int ();
                      cout << *(new int () - 16) + *(new int () - 16);
                      return 0;
                  }
                  
                  • @ 2024-2-22 10:55:40

                    改一下不用变量的做法

                    //不用变量
                    #include <iostream>
                    using namespace std;
                    
                    int main ()
                    {
                        cin >> *new int () >> *new int ();
                        cout << *(new int () - 16) + *(new int () - 16) + 1;
                        return 0;
                    }
                    
                • 1
                  @ 2023-11-11 18:10:17

                  没啥可说的,上代码 #include using namespace std; int main() { int a,b; cin>>a>>b; cout<<a+b; return 0; }

                  • 0
                    @ 2025-7-13 21:49:27
                    using namespace std;
                    int main()
                    {
                        char s1[1001],s2[1001];
                        int a[1001] = {},b[1001] = {},c[1001] = {};
                        cin>>s1>>s2;
                        int lena = strlen(s1);
                        int lenb = strlen(s2);
                        for(int i=0;i<=lena-1;i++)
                        {
                            a[i] = s1[lena - 1 - i] - '0';
                        }
                        for(int i=0;i<=lenb-1;i++)
                        {
                            b[i] = s2[lenb - 1 - i] - '0';
                        }
                        int lenc;
                        if(lena>lenb)
                        {
                            lenc = lena;
                        }
                        else
                        {
                            lenc = lenb;
                        }
                        int jw = 0;
                        for(int i=0;i<=lenc-1;i++)
                        {
                            c[i] = a[i]+b[i]+jw;
                            jw = c[i]/10;
                            c[i] = c[i]%10;
                        }
                        if(jw==1)
                        {
                            cout<<1;
                        }
                        for(int i=lenc-1;i>=0;i--)
                        {
                            cout<<c[i];
                        }
                        return 0;
                    }
                    
                    
                  • 1

                  信息

                  ID
                  1
                  时间
                  1000ms
                  内存
                  64MiB
                  难度
                  4
                  标签
                  递交数
                  273
                  已通过
                  126
                  上传者